Saturday, March 6, 2010

Welcome

Welcome to the MTH 121 blog. Feel free to post and comment on any matter in MTH 121 - Trigonometry.

4 comments:

  1. The following link contains information about the first set of lectures.
    http://www.analyzemath.com/Trigonometry.html

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  2. A tower stands on level ground. From a point P on the ground, the angle of elevation of the top of the tower is 26. Another point Q is 3m vertically above P and from this point the angle of elevation of the top of the tower is 21.Find the height of the tower. The problem refers to a triangle ABC. The answer should be 14.1 but I am unable to prove this fact.

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  3. QUES (posted by student) A tower stands on level ground. From a point P on the ground, the angle of elevation of the top of the tower is 26. Another point Q is 3m vertically above P and from this point the angle of elevation of the top of the tower is 21.Find the height of the tower. The problem refers to a triangle ABC. The answer should be 14.1 but I am unable to prove this fact.

    ANS: Use the sine rule to solve this problem. Consider the tower whose top is denoted by T. Now considering triangle PQT, use the sine rule to find length of side PT, using 111^0 and 5^0 and side 3m. After find PT, use this with the sine ratio to find the height of the tower. The sine rule will be covered in a later lecture.

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